2013

Label: Not On Label (Low Entropy Self-released) - none • Format: File MP3, Mixed 320 kbps • Country: Germany • Genre: Electronic • Style: Hardcore, Breakcore, Speedcore, Dark Ambient

So we can say that the information entropy of macrostates 0 and 2 are ln 1 which is zero, but the information entropy of macrostate 1 is ln 2 which is about 0. Of all the microstates, macrostate 2 accounts for half of them. It turns out that if you flip a large number of coins, the macrostates at or near half heads and half tails accounts for almost all of the microstates.

In other words, for a million coins, you can be fairly sure that about half will be heads and half tails. The macrostates around a ratio of heads to tails will be the "equilibrium" macrostate. A real physical system in equilibrium has a huge number of possible microstates and almost all of them are the equilibrium macrostate, and that is the macrostate you will almost certainly see if you wait long enough.

In the coin example, if you start out with a very unlikely macrostate like all heads, for example with zero entropy and begin flipping one coin at a time, the entropy of the macrostate will start increasing, just as thermodynamic entropy does, and after a while, the coins will most likely be at or near that macrostate, which has the greatest information entropy - the equilibrium entropy.

The macrostate of a system is what we know about the system, for example the temperature , pressure , and volume of a gas in a box. For each set of values of temperature, pressure, and volume there are many arrangements of molecules which result in those values. The number of arrangements of molecules which could result in the same values for temperature, pressure and volume is the number of microstates.

The concept of information entropy has been developed to describe any of several phenomena, depending on the field and the context in which it is being used. When it is applied to the problem of a large number of interacting particles, along with some other constraints, like the conservation of energy, and the assumption that all microstates are equally likely, the resultant theory of statistical mechanics is extremely successful in explaining the laws of thermodynamics.

Ice melting provides an example in which entropy increases in a small system, a thermodynamic system consisting of the surroundings the warm room and the entity of glass container, ice and water which has been allowed to reach thermodynamic equilibrium at the melting temperature of ice. This is always true in spontaneous events in a thermodynamic system and it shows the predictive importance of entropy: the final net entropy after such an event is always greater than was the initial entropy.

Later, the term came to acquire several additional descriptions, as more was understood about the behavior of molecules on the microscopic level. In the late 19th century, the word "disorder" was used by Ludwig Boltzmann in developing statistical views of entropy using probability theory to describe the increased molecular movement on the microscopic level.

That was before quantum behavior came to be better understood by Werner Heisenberg and those who followed. Descriptions of thermodynamic heat entropy on the microscopic level are found in statistical thermodynamics and statistical mechanics.

For most of the 20th century, textbooks tended to describe entropy as "disorder", following Boltzmann's early conceptualisation of the "motional" i. More recently, there has been a trend in chemistry and physics textbooks to describe entropy as energy dispersal.

Thus there are instances where both particles and energy disperse at different rates when substances are mixed together. The mathematics developed in statistical thermodynamics were found to be applicable in other disciplines.

In particular, information sciences developed the concept of information entropy , which lacks the Boltzmann constant inherent in thermodynamic entropy.

From Wikipedia, the free encyclopedia. This article has multiple issues. Please help improve it or discuss these issues on the talk page. Learn how and when to remove these template messages. This article may be too technical for most readers to understand. In both cases, there are no gases on the left-hand side of the equation, but carbon dioxide appears on the right.

Entropy will increase during such a reaction, because of the increased disorder. In this case, there is a decrease in entropy during the forward reaction because there are fewer gas molecules than you had to start with. That means that there fewer ways of arranging the energy of the system over those molecules, and so entropy decreases.

This is just a crystalline solid going into solution. The solid is highly ordered; the solution is disordered. There is an increase in entropy. The water is changing from the highly disordered gas into a more ordered liquid. The entropy will fall. There are three moles of gas on the left-hand side of the equation, but only one on the right. The starting materials are more disordered than the products, and so there is a decrease in entropy.

Notice that if the water had been formed as steam, you couldn't easily predict whether there was an increase or a decrease in entropy, because there would be three moles of gas on each side.

The presence of the five moles of liquid water on the left-hand side means that there will be far more disorder before the change than there is in the products. The copper II sulphate crystals formed will be very ordered. Entropy will decrease. Because this is all covered in detail in my calculations book I shan't be setting any questions throughout this section on entropy and free energy.

More energy gives you greater entropy and randomness of the atoms. Or search the sites for a specific topic. Useful Reference Materials Encyclopedia. Physics4Kids Sections. Go for site help or a list of physics topics at the site map! Then, by externally forcing ideally slowly the separating membranes together, back to contiguity, work is done on the mixed gases, fictively reversibly separating them again, so that heat is returned to the heat reservoir at constant temperature.

Because the mixing and separation are ideally slow and fictively reversible, the work supplied by the gases as they mix is equal to the work done in separating them again. Passing from fictive reversibility to physical reality, some amount of additional work, that remains external to the gases and the heat reservoir, must be provided from an external source for this cycle, as required by the second law of thermodynamics, because this cycle has only one heat reservoir at constant temperature, and the external provision of work cannot be completely efficient.

For entropy of mixing to exist, the putatively mixing molecular species must be chemically or physically detectably distinct. Thus arises the so-called Gibbs paradox , as follows. If molecular species are identical, there is no entropy change on mixing them, because, defined in thermodynamic terms, there is no mass transfer , and thus no thermodynamically recognized process of mixing. Yet the slightest detectable difference in constitutive properties between the two species yields a thermodynamically recognized process of transfer with mixing, and a possibly considerable entropy change, namely the entropy of mixing.

The "paradox" arises because any detectable constitutive distinction, no matter how slight, can lead to a considerably large change in amount of entropy as a result of mixing. Though a continuous change in the properties of the materials that are mixed might make the degree of constitutive difference tend continuously to zero, the entropy change would nonetheless vanish discontinuously when the difference reached zero.

From a general physical viewpoint, this discontinuity is paradoxical. But from a specifically thermodynamic viewpoint, it is not paradoxical, because in that discipline the degree of constitutive difference is not questioned; it is either there or not there.

Gibbs himself did not see it as paradoxical. Distinguishability of two materials is a constitutive, not a thermodynamic, difference, for the laws of thermodynamics are the same for every material, while their constitutive characteristics are diverse. Though one might imagine a continuous decrease of the constitutive difference between any two chemical substances, physically it cannot be continuously decreased till it actually vanishes.

Yet they differ by a finite amount. The hypothesis, that the distinction might tend continuously to zero, is unphysical. This is neither examined nor explained by thermodynamics. Differences of constitution are explained by quantum mechanics, which postulates discontinuity of physical processes.

For a detectable distinction, some means should be physically available. One theoretical means would be through an ideal semi-permeable membrane. The entirety of prevention should include perfect efficacy over a practically infinite time, in view of the nature of thermodynamic equilibrium. Even the slightest departure from ideality, as assessed over a finite time, would extend to utter non-ideality, as assessed over a practically infinite time. Such quantum phenomena as tunneling ensure that nature does not allow such membrane ideality as would support the theoretically demanded continuous decrease, to zero, of detectable distinction.

The decrease to zero detectable distinction must be discontinuous. For ideal gases, the entropy of mixing does not depend on the degree of difference between the distinct molecular species, but only on the fact that they are distinct; for non-ideal gases, the entropy of mixing can depend on the degree of difference of the distinct molecular species. The suggested or putative "mixing" of identical molecular species is not in thermodynamic terms a mixing at all, because thermodynamics refers to states specified by state variables, and does not permit an imaginary labelling of particles.

Only if the molecular species are different is there mixing in the thermodynamic sense. The entropy change of the reservoir is. The entropy change of the device is zero, because we are considering a complete cycle return to initial state and entropy is a function of state.

The surroundings receive work only so the entropy change of the surroundings is zero. The total entropy change is. Muddy Points What is the difference between the isothermal expansion of a piston and the forbidden production of work using a single reservoir?

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